Hello everyone, nerd here, and as always there's some math going on in this puzzle. The diagram can actually be viewed as a network with nodes being intersections of various lines, so this problem falls in the realm of graph theory. In a nutshell, what they are trying to construct is called an Euler Path through the network (Euler is pronounced "oil-er"), where each line segment is traversed exactly once. Whether or not you can actually do this depends on the 'degree' of each node in the network (i.e. the number of lines intersecting at the point). In this case, each intersection has degree 2, except midway up the vertical line, and the rightmost intersection (the edge of the boat on the right), which both have degree 3. This is exactly what you need to construct an Euler path (exactly two nodes of odd degree), and in fact every Euler path in this picture has to start and end at these two points.

This is so easy though 😂😂😂

How could anyone not get it after the first guy practically showed you the right way

These guys have a combined IQ of 6, so it's pretty difficult for them.

Ii

​@Savagedgĝgg 1 was in az az, academy

@Eric zhang are you blindfolded ? You’re the fourth person to reply with the same comment . We get it

They were blindfolded

This problem is a great introduction to discrete mathematics

This game is so easy 😂😂😂

I just noticed there's two ways to do it but white hoodie did it the least common way. Nice! 👍

There are at least 5 i could find

​@이이 there are way more then 7, you start at the top which gives you two options, up or left, u finish the flag and go down to the 4 way intersection, this gives you 3 more ways to continue racking up the Total to 6, from there u get to the 3 pointer eventually which gives you 2 options making it i think 12 from the top alone

Yeah same

@Isla MacMahon same, but they all do the flag first

Yes. The easiest way was not the one he did

the solution is so easy lmao

The trick to Euler circuits is by starting and ending at a vertex that has an odd number of paths coming from it. Or at least that helps in finding the solutions to the hard ones.

Yeah there’s 2 odd nodes in this one. You start from one and end on the other.

​@Your mom gaeYes, it is a path. Euler Paths traverse every edge exactly once, but can visit each vertex as many times as necessary.

This is an euler's path though no? An euler circuit cannot have odd number of edges on it. A circuit is a closed walk A path is a walk with no shared edges. In fact its not a path either i think, since it repeated a vertice. So its an eulers trail. If that is a thing

Now that's some actual good piece of information

I see you took a course on networks as well

Using Euler's path, we need to start from the bottom-left corner of the flag or in the rightmost part of the ship (the bottom right point the the triangle).

There are 2 ways to solve this and its rather simple.

Pro tip: the two intersections with exactly 3 lines going into them are the start / end points

@Ω it’s possible for a puzzle not to work with two odd-numbered intersections. it’s also possible for a puzzle to work with one or zero odd-numbered intersections

Also, puzzles like this work if and only if there are exactly two intersections with an odd number of lines going into them. If there are no intersections like this then the puzzle will be too easy, if there are more than two then the puzzle will be impossible.

👍

That exactly how I did it

Start from the box and use the bottom right and trace it- It’s so easy 😒

This is half Euler's graph. It has exactly two vertex with odd degrees(3). Therefore to create an Euler's path you should start with any vertex with odd dergee

This shape has exactly two vertices with an odd number of edge. One at the flag, one on the right. If you have noticed that it done, just done : I am pretty sure you can’t even mess that up if you start from either of this point, event if you wanted to.

That's the easiest puzzle I've ever seen

yea

Ikr

litterally

There’s also so many ways to do it

Yes

I started at the bottom intersection of the flag then moved my way from there. When I got to the triangle bit after doing the curve from left to right it went and follower the triangle up and down and turned right to complete it. Without crossing any of the lines

That is easy how the last one did it that how I was thinking to do it

I also found another way to beat the puzzle

How can you NOT see it ?!?!???!?

Here is the math behind it for people who are interested: This picture is doable because it has only two points where three (essentially an odd number) different paths meet: the right side of the boat and the bottom of the flag meeting the pole. You have to start at one of these two points.

It's a eulerian path that is connected and has at most 2 odd degree vertices

Ah yes someone else knows his graph theory

And you end at the other* All the others must be even, as you enter the intersection, and then leave.

He still crossed the line. So it’s still not possible.

The fact that everyone failed miserably except one person when woody literally nearly had it the first go, everyone should’ve copied him🤦🏻‍♂️

solo tienes que empezar desde arriba en la bandera, en la parte de abajo, subes te vas por el bastón y bajas , te vas hacia el triángulo, cruzas por el medio y luego terminas la curva de abajo. no tiene mucha ciencia, solo tardarás un par de minutos si ves las diferentes alternativas.

They're not solving it on purpose, for views

It was so perfect he could walk through it 😭

Fun fact this is from an area of mathematics called graph theory what they are trying to find is a “Euler path” (pronounced like oiler). Simply put a graph has an Euler path if at most 2 vertices (connecting points) has an odd number off edges (lines) leaving it. Therefore to find an Euler path you would have to start at one of these points and you will find if you do it correctly you will end at the other point. I recommend a square with a diagonal line through it if you want to test it out.

It can easily be solved using Euler's geometry trick where a complete structure must either have 0 or 2 odd nodes, if it has 0 odd nodes start wherever you want and it'll still end up at exactly same place if it has 2 odd nodes then start at an odd node and it'll surely end in the 2nd odd node

Anyone noticed last guy wasn’t wearing a blindfold

With all these puzzles, you start and end on a side with an uneven number of lines coming out. Something to do with Euler.

The satisfaction I got when white hoodie started from that point

The correct way is the way the first guy did.. the only thing he did wrong was that he started from the top of the triangle, he should've started from the right point to the top of the triangle.

​@Lovinq._.🧁B4K3R Ppppp

​8l

It's still wrong. He crossed the red line

Good

I saw it right away you got to start at the square go down the pole, then down the smaller part of the boat, around the bottom, up on top of the triangle and then finishing underneath the triangle 🤩

Pero si es super fácil

That’s not correct, he passed trough the lines

I have done this in three(3) ways : One from triangle 🔺 One from semi circle 🔴 One from square 🔲

Now I see who direct those game ads.

777, lucky!

мне 15 лет и я задаюсь вопросом.. вы что.. совсем тупые? это уровень ребёнка которому 4 года..

And even they managed it so seriously

😂😂😂😂

Best comment ever 💀😂

Pro tip: start and end on a vertex with an odd number of offshoot lines. If there are more than 2 such vertices, give up.

I got it on my first try and was wondering why no one was getting it but the last guy did it the same way I did it lol it was so simple

I found like 3 other ways to achieve that. They all start from the top left box corners. The flag of the ship!

multiple solutions to this one

Now I see why they need to award points for writing your name correctly on tests.

Using Euler walk, it's possible to do it as there are two vertices with odd degree

You can also strat with the triangle. It is the easiest puzzle ever

The trick is to always start and end at nodes with an odd number of lines

I don't know if they can't really find out to solve this puzzle or just to waste our time 😂

BRUH how are they struggling with this.. 😭

For you to comment this...

Start at the bottom of the flag moving left, up and around the flag and down the flagpole then right up over the triangle, across the horizon and then around the half circle.

Even the last one failed he crossed over his starting point. Start points to the right going left then bottom loop the v and up to make the box

Why aren’t we surprised of how they can keep their red lines perfectly in the while without messing up? 😭

Cause it’s edited? Maybe get some glasses

you could actually start with the vertical line up above and it connects everything else

Nice acting skills guys! Never seen people struggle over puzzles that easy to solve before, props to you!

bro they're having fun and that's all there is, people are probably miserable around you.

250th like

@🛡️ومِنهم مَن ينتظِر bro what does this have to do with puzzles

litterally the l easiest puzzle i’ve ever seen, and i’m a cuber so i have a right to say that

All you have to do is start with the horizontal line from one end to the other or end with it.

I was sitting there already knowing 2 ways to solve it XD

I feel like this is actually an incorrect solution, instead of going right; he should have gone left after the flag.

I'm sitting here the entire time seeing FOUR ways to solve this and losing my mind cz they can't see ANY one!😭🥴

Start with the flag!!!😢😮

I drew it as they were and solved it first try

Literally 😂

Its because its staged

@Skelyboss BUT... 😟 It only creates animosity

Thought for 2 seconds and see the way

He still didn't even do it right at the end 🤣

Bro this is literally the easiest puzzle even a 4 year old could beat it🤣

I would like to thank these mouth breathers for making me feel smart. I had this solved in 5 seconds.

正確解法：從「角有奇數個邊」的畫起到另一個「角有奇數個邊」結束 判斷：任意圖形的角只要符合「只能有『兩個以下』的角是有奇數個邊」就能一筆畫畫出 原理：任何圖形開始畫的角永遠都是有奇數個邊的，除了一筆畫開始和結束都是同一個點，那圖形就沒有「角有奇數個邊」 舉例：「日」 這個圖形為共兩個「角有奇數個邊」 「白」 這個圖形共四個「角有奇數個邊」，不符合

Bro typed out a school essay

Is really easy

alternatively, first straight horizontal lines from left to right then half circle left to right then triangle top two sides right to left then finally vertical line and square. finish Ed.

It's so simple that I want to cry

This... Could technically be a math problem on Graph Theory.... An easy as hell problem but still

First quick few seconds looking I’ve already solved it. 😝🤣🤣

I'm weird so here is a guide on another way to solve it. Start on the bottom right of the triangle at the top and go up, then down to the left, and go right. Go through the upside down arc and then go right. Once you reach the end of the triangle, go up to the very top of the flagpole and go ti the left, down, and right, or go to the bottom of the flag, left, up, right, then down to the end of the line.

始点と終点を逆にしたルートを同じとすると2×3!=12通りかな

De primeira ja achei a forma certa 😁

Aint no way it took them that long to figure it out. It clicked in my head as soon as I saw it

​@Eetmah Bykechorts Exactly the best way would have gone the length and came back around undermeath

Estuvo facil

They still didn't get jt right

I didn’t realize you could go over the same corner/point twice so I thought this was really hard

@King Mathieu Mnht7i

Flag, then the triangle, then the half circle. It took me 5 seconds of brain power to see this…

I was able to tell how to do it so fast 🙂

Así Como La Finalizó El De Blanco También Se Puede Hacer Haciendo Toda La Media Luna Y Cerrado Como Lo Hizo En El Video

Do the top from right to left, then down to the bottom, and then finally close up to the pole and then the flag.

When you realise that the first one did correctly if he started from straight right.

BRO 😂 u have to start at a point where the number of connections is UNEVEN. Thats ALWAYS the rule for solving such games. Simple

@B D Oh your are right, i didnt see that 1

@Drianol that’s not true. There’s another solution if you start at the right side of the largest horizontal line, go left, down, over the triangle, up the pole, and around the flag

@Lotta Roos yeah

Yeah, just doing the same but backwards lol

Me knowing that when the white time line at the bottom gets to the end somebody was going to win!

I literally figured it out before the first guy was even done. You literally have to start at the flag.

Eazy as hell. Start from the top work your way around the left

У меня получилось с первого раза, при том очень быстро!

For these: count the edges coming from the vertices. If there are ONLY two that have an odd number of edges, you must start at one and end at the other. Here, these two are at the bottom of the flag and upper right of the boat.

Yup I learned this about 2 seconds ago :not me just learning this

Yes, simple graph theory

Always do top to bottom like a maze put your left hand on the left wall and just walk

BRO I WAS IMAGINING THAT SAME THING IN MY HEAD AT THE END ONE🫢🫢🫢🫢

Tan difícil era de entender que hay que empezar por el único sitio que tiene una entrada y una salida? Is it so difficult to understand that you have to start with the only place that has an entrance and an exit? 😅😅

Są 2 sposoby

The difficult part was to act like not knowing to solve that easy puzzle 😂😂

Iudyx

@TheCanadianPainter like bro did in the video💀💀

@Mr Spike then how do you do it?

​@Kind Planet there are still 4 solutions without crossing lines

@Angel Espino my favorite puzzles are the east ones

Bro the first guy had it he was just off by one line 💀😂😂

By reading the puzzel i knew and saw instant how to solve it

Yes..thats so damn easy..that it took only 1.5 sec for me from the start of the video

Theres 2 ways to complete that kind of like the house with a x through the middle first the way the dude done it second is from right to left do the half circle the triangle then flag to finish

"Just act excited, they'll watch"

Start with the flag🏳😂😂 There is two ways to do this, from what I found out

Never start at the even Interactions. There are just two odd ones. Start there and it will allways work Out (Kuratowski: k-b+g=2)

It's so easy, got it in under 2 seconds

There are 2 different ways to do this… and i find it the both way… 💀

There’s also, almost a third way to do this, but idk If it counts, cause you pass by an angle, not 2x on line tho

Congrats your IQ is at least average

Just start from the end of the top of the half circle and just go from there

That was a actually easy you can solve it in multiple ways 💀

The sad thing is that I could solve these in seconds

There are so many different ways ways this could be solved tho

I just watched this twice without realizing it.

I literally solved it just looking at it for only 2 secs